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相关问题解答
1、4(2p+3q)²-(3p-q)²怎么算
答：[最佳答案] 方法一:4(2p+3q)²-(3p-q)²=[2(2p+3q)]²-(3p-q)²=[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]=(7p+5q)(p+7q) 方法二:4(2p+3q)²-(3p-q)²=4(4p²+12pq+9q²)-(9p²-6pq+q²)=16p²+48pq+36q²-9p²+6pq-q²=7p²+54pq+35q²=(7p+5q)(p+7q) ...
2、4(2p+3q)^2(3p-
答：[最佳答案] 您好:4(2p+3q)^2 -(3p-q)^2=16p^2+48pq+36q^2-9p^2+6pq-q^2=7p^2+54pq+35q^2 如果本题有什么不明白可以追问,如果满意请点击右下角“采纳为满意回答” 如果有其他问题请采纳本题后,另外发并点击我的头像向我求助,答题不易,请...
3、4(2p+3q)²-(3p-q)²怎么算
答：[最佳答案] 方法一:4(2p+3q)²-(3p-q)²=[2(2p+3q)]²-(3p-q)²=[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]=(7p+5q)(p+7q) 方法二:4(2p+3q)²-(3p-q)²=4(4p²+12pq+9q²)-(9p²-6pq+q²)=16p²+48pq+36q²-9p²+6pq-q²=7p²+54pq+35q²=(7p+5q)(p+7q) ...